On reductive ozonolysis,1-methylcyclohexene y | vedclass

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Question

(A) Reductive ozonolysis of an alkene involves the cleavage of the $C=C$ double bond and the addition of oxygen atoms to each carbon to form carbonyl

Vedclass · Accepted Answer

$6-$oxoheptanal

Vedclass · Answer

(A) Reductive ozonolysis of an alkene involves the cleavage of the $C=C$ double bond and the addition of oxygen atoms to each carbon to form carbonyl compounds.For $1-$methylcyclohexene,the $C=C$ bond breaks,opening the ring to form a linear chain.The carbon atom originally attached to the methyl group becomes a ketone $(C=O)$,and the other carbon of the double bond becomes an aldehyde $(-CHO)$.The resulting product is a $7-$carbon chain with a ketone group at position $6$ and an aldehyde group at position $1$,which is $6-$oxoheptanal.

On reductive ozonolysis,$1-$methylcyclohexene yields:

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